Sulfur is the element which can bond covalently with an oxygen atom to form a two-atom molecule.
A chemical element is a material that cannot be degraded chemically. Although chemical processes do not modify atoms, nuclear reactions can produce new elements.
Elements are classified based on the number of protons they have. An element's atoms all have the same amount of protons, but differing numbers of electrons as well as neutrons. Ions are formed by altering the electron-to-proton ratio, whereas isotopes are formed by changing the amount of neutrons. Sulfur is the element which can bond covalently with an oxygen atom to form a two-atom molecule.
Therefore, Sulfur is the element which can bond covalently with an oxygen atom to form a two-atom molecule.
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Answer:
A
Explanation:
The correct answer is "They conduct an electric current in a solution. "
Acids taste sour, and they turn blue litmus paper red. Also acids such as HCl when dissociates in water it releases H⁺ ions. Thus in an acid the concentration of H⁺ is greater than OH⁻.
HCl + H₂O -> H⁺ + Cl⁻
A base such as NaOH will dissociate in water to form Na⁺ and OH⁻. The ions of an aqueous solution of base will conduct electricity.
NaOH + H₂O -> Na⁺ + OH⁻
The volume of 53.0g of nitrogen dioxide gas at STP is 6.78 mol.
Chemically, nitrogen dioxide has the formula NO₂. It belongs to a group of nitrogen oxides. Millions of tons of nitric acid are produced annually for use largely in fertilizer manufacture, with NO₂ serving as an intermediary in this process. As the temperature rises, the gas turns reddish-brown.
Nitrogen dioxide is created when reactions between nitrogen oxide (NO) and other nitrogen oxides (NOx) and other airborne molecules occur. The burning of fossil fuels (coal, gas, and oil), particularly the fuel used in automobiles, is the largest source of nitrogen dioxide originating from human activity.
We have the number of moles of gas ( n ), by multiplying the given mass by the inverse of the molar mass of nitrogen gas, which exists in diatomic form given by
n = ( 53g ) × 128.02mol/g
= 6.78 mol
Thus, The volume of 53.0g of nitrogen dioxide gas at STP is 6.78 mol.
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We can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:
P1V1 =P2V2
P2 = P1 x V1 / V2
P2 = 0.12 x 2.31 / 7.14
P2 = 0.04 atm
Answer: 0.04 atm
Explanation:
Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.
(At constant temperature and number of moles)
where,
= initial pressure of gas = 0.12 atm
= final pressure of gas = ?
= initial volume of gas =
= final volume of gas = 7.14 L
Therefore, the final pressure of the air within the balloon is 0.04 atm.
Answer:
Some of the physical changes used by the industrial chemist in order to identify it is by scratching it with other metals in order to find the hardness of it. Trying to deform it in order to find the malleability, and to heat it and measure the temperature in order to find the melting point.
Some of the chemical changes used by the industrial chemist in order to identify it is by inserting it in water to observe that whether it reacts with it or not, if the reaction is violent, then the metal belongs to either group I or group II. The other method is to insert it in acids of distinct strength and to observe its reaction. The metals belonging to the second group react briskly with acids. The other metals react gradually with acids and others are almost inert.
Answer:
Some of the physical changes used by the industrial chemist in order to identify it is by scratching it with other metals in order to find the hardness of it. Trying to deform it in order to find the malleability, and to heat it and measure the temperature in order to find the melting point.
Some of the chemical changes used by the industrial chemist in order to identify it is by inserting it in water to observe that whether it reacts with it or not, if the reaction is violent, then the metal belongs to either group I or group II. The other method is to insert it in acids of distinct strength and to observe its reaction. The metals belonging to the second group react briskly with acids. The other metals react gradually with acids and others are almost inert.
Explanation:
Some of the symptoms from swallowing hydrochloric acid: