# An astronaut is using a drill to fix the gyroscopes on the Hubble telescope. Suddenly she loses her footing and floats away from the telescope. She should throw the drill in the direction opposite the telescope to give herself what? In the direction of the telescope

2 months ago

## Solution 1

Guest #2392202
2 months ago

a boost towards the direction. or she should have hooked herself up to a whire

Explanation:

## 📚 Related Questions

Question
Calculate the kinetic energy of a 10kg cart traveling at 4 m/s?
Solution 1

Answer: KE = 80 J

Explanation: Kinetic energy is expressed in this formula:

KE = 1/2 mv²

= 1/2 ( 10 kg) ( 4 m/s)²

= 1/2 (160 J)

= 80 J

Solution 2

Explanation:

Ke = 1/2mv2 = 1/2.10.(4)2=5.16= 80 J

Question
Find the momentum of a train with a mass of 850 kg and forward velocity of 15 m/s
Solution 1

P=12,750kgm/s

Explanation:

Momentum (P) = mass x velocity

Where velocity =15m/s

Mass=850kg

Therefore, momentum(P) = (850kg) x (15m/s)=12,750kgm/s

Hence,the momentum of the train is 12,750kgm/s

Solution 2

12,750

Explanation:

P = mv

Momentum = Mass x Velocity

Plug it in and finish equation

Question
A boy that has a mass of 40 kilograms is walking at a speed of 2m/s. What is the boys momentum?
Solution 1

Answer: p = 80 kg.m/s

Explanation: Momentum is expressed as the product of mass and velocity.

p= mv

= 40 kg ( 2 m/s)

= 80 kg.m/s

Solution 2

The boy's momentum = 80kgm/s

Explanation:

Momentum (P) =mass x velocity

Where, velocity(speed) =2m/s

Mass of the boy=40Kg

Momentum (P)=(40kg) x (2m/s) = 80kgm/s.

Question
you can produce a sound by plucking a string or by blowing into a pipe. how are these two sounds different
Solution 1

Explanation:

both are different types of energy. one is elastic p.e while the other one is made by change in sound waves

Question
A boy of mass 50 kg exerts a pressure of 25000 pa calculate the area which the force acts A = 0.02m²​
Solution 1

Answer: A = 0.02 m²

Explanation: Solution:

Pressure is expressed in the formula:

P = F / A       where F = mg

= mg /A

= 50 kg ( 9.8 m/s²) / 25000 Pa

=  0.02 m²

Question
When light shines on a metal surface, the maximum energies of emitted electrons: 1. vary with the intensity of the light 2. vary with the frequency of the light 3. vary with the speed of the light 4. are random
Solution 1
Vary with the frequency of the light
Question
When a photon collides with an electron and is deflected, the photon’s ____ decreases. 1. frequency 2. wavelength
Solution 1

2. Wavelength

Explanation:

When a photon collides with an electron and is deflected, the photon’s wavelength decreases.

When photon gained energy by the collision of the electron. Its energy and frequency will be increased and its wavelength will be decreased.

Solution 2

1. Frequency

Explanation:

When a photon collides with an electron, the effect of it is called Compton scattering, where the photons interact with the electron, losing momentum and therefore increase in wavelength and a decrease in frequency.

Question
When the speed of electrons striking the anode is increased, the of the ______ of the emitted x-rays increases 1. frequency 2. density 3. wavelength
Solution 1

The speed of electrons striking the anode is increased, the density of the emitted x-rays increases.

Explanation:

Whenever electrons are made to be incident on any anode, they will be interacting with the surface atoms of anode. So these interaction will lead to excitation of electrons of the surface atoms of the anode.

Thus when the excited electron will come back to ground state, it will emit x-rays. Thus, on increasing the speed of the striking electrons, it will gain the property of interacting with larger amount of surface atoms leading to increase in the emission of X-rays .

Thus, this increase in the emission of X-rays will lead to increase in the density of X-ray. So the speed of electrons striking the anode is increased, the density of the emitted x-rays increases.

Question
When the number of electrons striking the anode of an x-ray tube is increased, the ____ of the emitted X-Ray increases. 1. density 2. frequency
Solution 1
When the number of electrons striking the anode of an X-ray tube is increased, the density of the emitted x-ray increases
Question
What is the difference between analog and digital sound transmission?
Solution 1

In analog sound transmission, information is translated in electric pulses. In digital sound transmission, information is translated to binary codes of zero and one.

Explanation:

• Electric pulses in analog sound transmission has a range of amplitude. Binary format of digital sound transmission has only two types of amplitudes.
• The waves of analog transmission are sine waves while the waves in digital transmission are square waves.
• Analog signals consume less bandwidth while digital signals consume more bandwidth

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