How many moles are in 43 grams of lithium (LI)?

How many moles are in 43 grams of lithium (LI)?

2 months ago

Solution 1

Guest Guest #5493627
2 months ago

Answer:

6.19507275608684

Explanation:

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(Potential Energy)

The motionless wrecking ball doesn’t have any kinetic energy. But what would happen if it were lifted two stories up with a crane and suspended above a car? In this case, the wrecking ball isn't moving, but there is, in fact, still energy associated with it. The energy of the suspended wrecking ball reflects its potential to do work (in this case, damage). If the wrecking ball were released, it would do work by making a pancake of someone’s poor car. And if the ball is heavier, the energy associated with it will be greater.This type of energy is known as potential energy, and it is the energy associated with an object because of its position or structure. For instance, the energy in the chemical bonds of a molecule is related to the structure of the molecule and the positions of its atoms relative to one another. Chemical energy, the energy stored in chemical bonds, is thus considered a form of potential energy. Some everyday examples of potential energy include the energy of water held behind a dam, or of a person about to skydive out of an airplane.

Question
A compound is 44.82% Potassium, 18.39% Sulfur, and 36.79% Oxygen. Write the empirical formula and name the compound.
Solution 1

The empirical formula for the given compound has been \rm \bold{K_2SO_4}.

The empirical formula has been the simplest whole-number ratio of the atoms of each element present in the compound.

The atoms of K can be given by:

Atoms = \rm \dfrac{Percentage}{Molecular\;mass}

  • The atoms of K = \rm \dfrac{44.82}{36}

The atoms of K = 1.15

  • The atoms of S = \rm \dfrac{18.39}{32}

The atoms of S = 0.57

  • The atoms of O = \rm \dfrac{36.79}{16}

The atoms of O = 2.29

To obtain the whole number ratio, the atoms have been divided by the smallest atom number i.e. 0.57.

  • The atoms of K = \rm \dfrac{1.15}{0.57}

The atoms of K = 2

  • The atoms of S = \rm \dfrac{0.57}{0.57}

The atoms of S = 1

  • The atoms of O = \rm \dfrac{2.29}{0.57}

The atoms of O = 4

Thus, the empirical formula for the given compound has been \rm \bold{K_2SO_4}.

For more information about the empirical formula, refer to the link:

brainly.com/question/11588623

Solution 2

Answer:

Empirical formula = K₂SO₄

The name of the compound is Potassium tetraoxosulfate (vi)

Explanation:

Percentage composition of the elements:

Potassium = 44.82%

Sulfur = 18.39%

Oxygen = 36.79%

Mole ratio of the elements:

Potassium = 44.82/39 =1.15

Sulfur = 18.39/32 = 0.57

Oxygen = 36.79/16 = 2.29

Dividing by the smallest ratio in order to obtain the simplest ratio

Potassium = 1.15/0.57 =2

Sulfur = 0.57/0.57 = 1

Oxygen = 2.29/0.57 = 4

Therefore, the mole ratio of Potassium : Sulfur : Oxygen = 2:1:4

Empirical formula = K₂SO₄

The name of the compound is Potassium tetraoxosulfate (vi)