Solution 1
Answer:
amount of He = (7.91 × 10^22) ÷ (6.02 × 10^23) = 0.131mol (3sf)
Explanation:
you make use of the mole concept formula
amount(mol) = number of particles ÷ 6.02 × 10^23
(6.02 × 10^23 is the avogadro constant, which is an extremely important number in this formula for mole concept)
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(Potential Energy)
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The empirical formula for the given compound has been .
The empirical formula has been the simplest whole-number ratio of the atoms of each element present in the compound.
The atoms of K can be given by:
Atoms =
- The atoms of K =
The atoms of K = 1.15
- The atoms of S =
The atoms of S = 0.57
- The atoms of O =
The atoms of O = 2.29
To obtain the whole number ratio, the atoms have been divided by the smallest atom number i.e. 0.57.
- The atoms of K =
The atoms of K = 2
- The atoms of S =
The atoms of S = 1
- The atoms of O =
The atoms of O = 4
Thus, the empirical formula for the given compound has been .
For more information about the empirical formula, refer to the link:
Answer:
Empirical formula = K₂SO₄
The name of the compound is Potassium tetraoxosulfate (vi)
Explanation:
Percentage composition of the elements:
Potassium = 44.82%
Sulfur = 18.39%
Oxygen = 36.79%
Mole ratio of the elements:
Potassium = 44.82/39 =1.15
Sulfur = 18.39/32 = 0.57
Oxygen = 36.79/16 = 2.29
Dividing by the smallest ratio in order to obtain the simplest ratio
Potassium = 1.15/0.57 =2
Sulfur = 0.57/0.57 = 1
Oxygen = 2.29/0.57 = 4
Therefore, the mole ratio of Potassium : Sulfur : Oxygen = 2:1:4
Empirical formula = K₂SO₄
The name of the compound is Potassium tetraoxosulfate (vi)