How many moles are in 7.91 X 1022 atoms of He?

How many moles are in 7.91 X 1022 atoms of He?

2 months ago

Solution 1

Guest Guest #5493607
2 months ago

Answer:

amount of He = (7.91 × 10^22) ÷ (6.02 × 10^23) = 0.131mol (3sf)

Explanation:

you make use of the mole concept formula

amount(mol) = number of particles ÷ 6.02 × 10^23

(6.02 × 10^23 is the avogadro constant, which is an extremely important number in this formula for mole concept)

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Question
A compound is 44.82% Potassium, 18.39% Sulfur, and 36.79% Oxygen. Write the empirical formula and name the compound.
Solution 1

The empirical formula for the given compound has been \rm \bold{K_2SO_4}.

The empirical formula has been the simplest whole-number ratio of the atoms of each element present in the compound.

The atoms of K can be given by:

Atoms = \rm \dfrac{Percentage}{Molecular\;mass}

  • The atoms of K = \rm \dfrac{44.82}{36}

The atoms of K = 1.15

  • The atoms of S = \rm \dfrac{18.39}{32}

The atoms of S = 0.57

  • The atoms of O = \rm \dfrac{36.79}{16}

The atoms of O = 2.29

To obtain the whole number ratio, the atoms have been divided by the smallest atom number i.e. 0.57.

  • The atoms of K = \rm \dfrac{1.15}{0.57}

The atoms of K = 2

  • The atoms of S = \rm \dfrac{0.57}{0.57}

The atoms of S = 1

  • The atoms of O = \rm \dfrac{2.29}{0.57}

The atoms of O = 4

Thus, the empirical formula for the given compound has been \rm \bold{K_2SO_4}.

For more information about the empirical formula, refer to the link:

brainly.com/question/11588623

Solution 2

Answer:

Empirical formula = K₂SO₄

The name of the compound is Potassium tetraoxosulfate (vi)

Explanation:

Percentage composition of the elements:

Potassium = 44.82%

Sulfur = 18.39%

Oxygen = 36.79%

Mole ratio of the elements:

Potassium = 44.82/39 =1.15

Sulfur = 18.39/32 = 0.57

Oxygen = 36.79/16 = 2.29

Dividing by the smallest ratio in order to obtain the simplest ratio

Potassium = 1.15/0.57 =2

Sulfur = 0.57/0.57 = 1

Oxygen = 2.29/0.57 = 4

Therefore, the mole ratio of Potassium : Sulfur : Oxygen = 2:1:4

Empirical formula = K₂SO₄

The name of the compound is Potassium tetraoxosulfate (vi)

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