How many terms are in the algebraic expression 3x2 + 4y - 1? A. 2 B. 3

How many terms are in the algebraic expression 3x2 + 4y - 1? A. 2 B. 3 C. 5 D. 4

2 months ago

Solution 1

Guest Guest #2392205
2 months ago

The amount of terms in the algebraic expression is D.4

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What is the image of (-5,5) after a dilation by a scale factor of 4 centered at the origin?
Solution 1

The image of (-5,5) is (-20, 20).

What is image point?

Its image refers to the new position of a point, line, line segment, or figure following a transformation.

for instance, the image of the triangle A'B'C following translation is the triangle A'B'C. The images of points A, B, and C are represented by the letters A, B, and C. The images of the original line segments AB, BC, and AC are represented by the line segments A'B', B'C', and A'C', respectively.

Given coordinates  (-5,5) dilation by a scale factor of 4 centered at the

origin, If a point's preimage is P(x, y), then its image after a dilation with a scale factor of k and centered at the origin (0, 0) is P′(kx, ky).

Using this rule we can find the image of (-5 , 5)

Here P(x , y) = (-5 , 5) and k = 4

So P'(x , y) = 4(-5 , 5) = (-20, 20)

Hence the new coordinates are (-20, 20).

Learn more about image point;

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Solution 2

Answer:

x=-5 and y=5

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What is the equation of the line with the slope of 9 and the y-intercept of 13?
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y=9x+13

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Slope Int Formula is y=m(x)+b

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8, 6, 4, 2, 0, . . . Whats the value of the next sequence
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Step-by-step explanation:

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a=t1=8

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Rewrite the expression in the form y^n y^-7/y^-11
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Answer:

y^{4}

Step-by-step explanation:

Using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)}

Given

\frac{y^{-7} }{y^{-11} }

= y^{(-7-(-11))}

= y^{(-7+11)} = y^{4}

Question
Write y=2(x + 6)(x + 3) in standard form
Solution 1

Answer:

y = 2x² + 18x + 36

Step-by-step explanation:

Given

y = 2(x + 6)(x + 3) ← expand the factors using FOIL

y = 2(x² + 9x + 18) ← distribute parenthesis by 2

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Question
A pilot flying at an altitude of 3.7 km sights 2 control towers directly in front of him. The angle of depression to the base of one tower is 3 the angle of depression to the base of the other tower is 35. Part A: Find the distance the plane will travel to fly over the first tower. Round to the nearest hundredth. Part B: Find the distance the plane will travel to fly over the second tower. Round to the nearest hundredth.
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Part A; The plane will have to travel 70.61 km to fly over the first tower

Part B; The plane will have to travel 5.28 km to fly over the second tower

Step-by-step explanation:

Step 1; Assume the plane is x km away from the control tower. We know it is flying at a height of 3.7 km and an angle of depression of 3°. So a right-angled triangle can be formed using these measurements. The triangle's opposite side measures 3.7 kilometers while the opposite side measures x kilometers. The angle of the triangle is 3°

Step 2; Since we have the length of the opposite side and the angle of the triangle, we can determine the tan of an unknown angle.  

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x = 70.6106 kilometers.

So the plane must travel 70.61 km to fly over the first tower.

Step 3; Assume the plane is y km away from the control tower. We know it is flying at a height of 3.7 km and an angle of depression of 35°. So a right-angled triangle can be formed using these measurements. The triangle's opposite side measures 3.7 kilometers while the opposite side measures y kilometers. The angle of the triangle is 35°

Step 4; Since we have the length of the opposite side and the angle of the triangle, we can determine the tan of an unknown angle.  

tan 35°= \frac{3.7}{y}, y =  \frac{3.7}{tan35}, tan 35° = 0.7002,

y = 5.2842 kilometers.

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Step-by-step explanation:

40.4 kg = 40.40 kg which is rounded to the nearest hundreth.

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Step-by-step explanation:

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Step-by-step explanation:

Let \:   \: \theta =  \sin^{ - 1}  (\frac{4}{5})  \\  \\  \therefore \:  \sin\theta = \frac{4}{5} \\  \\  \because \:  { \cos}^{2} \theta =1  - { \sin}^{2} \theta  \\  \\  \therefore \: { \cos}^{2} \theta  = 1 - (\frac{4}{5} )^{2}  \\ \\   = 1 -  \frac{16}{25}  \\  \\  =  \frac{25 - 16}{25}  \\  \\  =  \frac{9}{25}  \\  \\   \therefore \:{ \cos}\theta  = \pm \:  \frac{3}{5}  \\  \\  \because \:  \theta \: lie \: in \: the \: first \: quadrant \\  \\  \therefore \: { \cos}\theta  =  \:  \frac{3}{5}  \\ \\  \implies \theta =  { \cos}^{ -1 }  \: \frac{3}{5}\\\\\implies \theta =  { \cos}^{ -1 }  \: \frac{3}{5}= { \sin}^{ -1 }  \: \frac{4}{5} \\  \\  \therefore \:  \cos( \ {sin}^{ - 1}  \frac{4}{5} ) \\ \\ =  \cos( \ {cos}^{ - 1}  \frac{3}{5} )   \\\\ = \frac{3}{5}  \\  \\   \purple{ \boxed{\therefore \: \cos( \ {sin}^{ - 1}  \frac{4}{5} ) = \frac{3}{5}}}

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Which two reactans can be used to make the salt called sodium chloride​
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Sodium and Chlorine

Step-by-step explanation:

Hence the name sodium chloride or salt

Solution 2

A combination reaction is one in which two or more substances (the reactants) are combined directly to form a single product (the product). An example is the reaction in which sodium (Na) combines with chlorine (Cl 2 ) to form sodium chloride, or table salt (NaCl)