admin

2 months ago

Guest #6877021

2 months ago

The correct answer is D.

Question

Which expressions show the expanded form for 403.08? Choose all answers that are correct. A. 4 Ã— 100 + 3 Ã— 1 + 0 Ã— + 8 Ã— B. 4 Ã— 100 + 0 Ã— 10 + 3 Ã— 1 + 0 Ã— + 8 Ã— C. 4 Ã— 100 + 3 Ã— 1 + 8 Ã— D. 4 Ã— 100 + 0 Ã— 10 + 3 Ã— 1 + 0 Ã— + 8 Ã—

Solution 1

A. 4 Ã— 100 + 3 Ã— 1 + 0 Ã— + 8 Ã—

Â Â B. 4 Ã— 100 + 0 Ã— 10 + 3 Ã— 1 + 0 Ã— + 8 Ã—

Â Â C. 4 Ã— 100 + 3 Ã— 1 + 8 Ã—

Â Â D. 4 Ã— 100 + 0 Ã— 10 + 3 Ã— 1 + 0 Ã— + 8 Ã—Â

A and C are the same as B and D. However none equal to 403.08

Ac= 403

Bd= 411

Â Â B. 4 Ã— 100 + 0 Ã— 10 + 3 Ã— 1 + 0 Ã— + 8 Ã—

Â Â C. 4 Ã— 100 + 3 Ã— 1 + 8 Ã—

Â Â D. 4 Ã— 100 + 0 Ã— 10 + 3 Ã— 1 + 0 Ã— + 8 Ã—Â

A and C are the same as B and D. However none equal to 403.08

Ac= 403

Bd= 411

Question

Anthony is making a collage for his art class by picking shapes randomly. He has five squares, two triangles, two ovals, and four circles. Find P(a triangle or a square is chosen first).

Solution 1

**Answer:**

P(a triangle or a square is chosen first)

**Step-by-step explanation:**

Probability of an outcome is the ratio of number of favorable outcome to total number of outcomes.

Total number of outcomes= 5 + 2 + 2 + 4 = 13

P(a triangle or a square is chosen first) = P(a triangle chosen first) + P(a square chosen first)

P(a triangle or a square is chosen first) Â Â Â Â Â

Solution 2

There total quantity of shapes is 5 + 2 + 2 + 4 = 13. The total quantity of triangles and squares is 2 + 5 = 7. The probability of choosing a triangle or a square first is 7/13

Question

if the data represented by the graph is normally distributed, what are the endpoints of the middle 95% of the data

Solution 1

By using the empirical rule of a normal distribution, If the data represented by the graph is normally distributed, the endpoints of the middle 95% of the data are "(D) 2.4 and 13.2."

There exists the same question from other source with the following choices:

(A) 4.2 and 11.4

(B) 6 and 9.6

(C) 4.2 and 9.6

(D) 2.4 and 13.2

(E) 6 and 11.4

There exists the same question from other source with the following choices:

(A) 4.2 and 11.4

(B) 6 and 9.6

(C) 4.2 and 9.6

(D) 2.4 and 13.2

(E) 6 and 11.4

Question

Make a subject of the formula:
t=a-6
help please?

Solution 1

T + 6= a

6 = a - t

6 = 12 - 6

SO:

t= 6

a= 12

6 = a - t

6 = 12 - 6

SO:

t= 6

a= 12

Question

Translate the equation m = 5 - n to a verbal model.

Solution 1

M equals five minus n ?

Question

Which scatter plot represents the data in the table? Park patrons Number of dogs
7 4
6 2
9 7
8 6
5 3
7 7
3 1
4 3

Solution 1

In order to answer this question, you need to know what should be in the x axis and what should be in the y axis.

As for this one, you have given the information of the table:

Park patrons Number of dogs

7 4

6 2

9 7

8 6

5 3

7 7

3 1

4 3

The value in the x axis should be theÂ Park patrons

The value in the y axis should be the Number of dogs

As for this one, you have given the information of the table:

Park patrons Number of dogs

7 4

6 2

9 7

8 6

5 3

7 7

3 1

4 3

The value in the x axis should be theÂ Park patrons

The value in the y axis should be the Number of dogs

Question

There are 10 grams of fat in a serving of sausage. Each serving is 100 calories. How many calories are from fat

Solution 1

10 calories i believe because if you divide 100 divided by 10 that will equal 10

Solution 2

10 calories I think because

100/10=10

100/10=10

Question

What is the 10th term in the pattern with the formula 5n + 100?

Solution 1

Easy

first term is n=1

so 10th term is n=10

5(10)+100=50+100=150

150 is 10th term

first term is n=1

so 10th term is n=10

5(10)+100=50+100=150

150 is 10th term

Question

Gavin and Seiji both worked hard over the summer. Together, they earned a total of $425. Gavin earned $25 more than Seiji. How much did each of them earn? (a) Write a system of two equations with two variables to model this problem.
(b) Use substitution or the elimination method to solve the system.
(c) Graph both equations.
(d) Answer the question.

Solution 1

Let the money Seiji got be x and Gavin, y.

Total is 425.

So, x + y = 425

Gavin got 25 more than Seiji.

So, y = x + 25

I will use substitution method.

Substitute y = x + 25 in x + y = 425.

x + x + 25 = 425

2x + 25 = 425

2x = 400

x=$200

So, x is Seiji and he got $200.

For Gavin, substitute x in the equation of y.

y = x + 25

y = 200 + 25

y = $225

So, y is Gavin and he got $225.

For the graph part, I don't know how to show you. Hope you will be able to do the rest by yourself. If you need help with graphing, you may use desmos.com

Total is 425.

So, x + y = 425

Gavin got 25 more than Seiji.

So, y = x + 25

I will use substitution method.

Substitute y = x + 25 in x + y = 425.

x + x + 25 = 425

2x + 25 = 425

2x = 400

x=$200

So, x is Seiji and he got $200.

For Gavin, substitute x in the equation of y.

y = x + 25

y = 200 + 25

y = $225

So, y is Gavin and he got $225.

For the graph part, I don't know how to show you. Hope you will be able to do the rest by yourself. If you need help with graphing, you may use desmos.com

Solution 2

200 for Seiji, and 225 for Gavin.

Question

2. The length of a rectangle is 5 mm longer than its width. Its perimeter is more than 30 mm. Let w equal the width of the rectangle. (a) Write an expression for the length in terms of the width.
(b) Use expressions for the length and width to write an inequality for the perimeter, on the basis of the given information.
(c) Solve the inequality, clearly indicating the width of the rectangle.

Solution 1

P=2(L+W)

L=5+W

P>30

30<2(L+W)

divide 2

15<L+W

15<5+W+W

15<5+2W

minus 5

10<2W

divde 2

5<W

A. L=5+W

B. P=2(5+W+W)

C. 5<W

L=5+W

P>30

30<2(L+W)

divide 2

15<L+W

15<5+W+W

15<5+2W

minus 5

10<2W

divde 2

5<W

A. L=5+W

B. P=2(5+W+W)

C. 5<W

Mathematics
2647929

History
842281

English
748681

Biology
586256

Social Studies
406852

Chemistry
368373

Business
348603

Physics
324927

Health
199835

Spanish
130075

Geography
112100

Computers and Technology
106146

Arts
77164

Advanced Placement (AP)
23675

World Languages
23213

French
22589

Engineering
19607

Law
17108

Medicine
13966

SAT
10987

German
3389

High School
3423409

Middle School
2092250

College
1518097