 admin # Prepare ~ 8.75 × 10–4 M CrO4 solution from the ~1.25× 10–3 M K2CrO4 stock solution. Record the exact molarity of the stock solution. Calculate the required amount of stock solution to make 10.00 mL of dilute solution. Adjust this value as necessary (ratio) based on the volumetric flask available.

2 months ago

## Solution 1 Guest #1625861
2 months ago

7 mL

Explanation:

To prepare a solution by dilution of another one, we can use the equation:

C1V1 = C2V2

where C is the concentration, V is the volume, 1 is the initial solution, and 2 the final solution. V represents the total volume. K₂CrO₄ dissolver by:

K₂CrO₄ → 2K⁺ + CrO₄⁻²

So, 1 mol of K₂CrO₄ results in 1 mol of CrO₄⁻², the in a solution of 8.75x10⁻⁴M of CrO₄⁻², it will be 8.75x10⁻⁴M of K₂CrO₄, so the volume of the stock solution will be:

1.25x10⁻³xV1 = 8.75x10⁻⁴x10

V1 = (8.75x10⁻³)/(1.25x10⁻³)

V1 = 7 mL

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2.5 M

Explanation:

To address this question, we can use the dilution formula:

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Where M1 is the concentration of the concentrated solution

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V2 is the volume of the diluted solution or the final volume.

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Option 6 ) Neutralization

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Explanation: (Unbalanced)

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(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms

3 × 1 × 2 = 6, P atoms

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Reactant side           Number of atoms or groups                   Product side

of each element

3                                                 Ba                                                           3

2 2

12                                                H                                                             2

6                                                 O (Exclude O of )         1

To balance H and O, multiply by 6 so we have Reactant side           Number of atoms or groups                    Product side

of each element

3                                                 Ba                                                           3

2 2

12                                                H                                                            12

6                                                 O (Exclude O of )        6

Balanced!!!!

Acid and base reacts to form salt and water is called a neutralization reaction.

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Explanation:

Balancing is making the number of atoms of each element same on both the sides  (reactant and product side).

To find the number of atoms of each element we multiply coefficient and the subscript

For example contains

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example we multiply coefficient × subscript × number outside the bracket to find the number of atoms

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms

3 × 1 × 2 = 6, P atoms

3 × 4 × 2 = 24, O atoms are present

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Reactant side           Number of atoms or groups                   Product side

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3                                                 Ca                                                           1

2                                                  N                                                            2

12                                                H                                                            8

6                                                  O                                                            2

Multiplying on the right side by 3, we will have Reactant side           Number of atoms or groups                   Product side

of each element

3                                                 Ca                                                           3

2                                                  N                                                            2

12                                                H                                                            12

6                                                  O                                                            6

Balanced!!!!

Solution 2

3: double displacement

Question
HELP WILL GIVE BRAINLIESTWhich of these elements would have the largest ionic radius? Bi3+ C4- Li+ Na+ Cl-
Solution 1

Ions can be made by single element or covalently bonded group of elements. The covalently bonded group of elements is called polyatomic ions or polyatomic atoms. Therefore, C⁴⁻ is the largest among all.

### What is Ions?

Any species that contain charge whether it is positive charge or negative charge is called ions. The example of polyatomic ions are sulfate, phosphate, nitrate etc.

Cation is the species that loose electron and attain positive charge while anion is a species which gain electron and attains negative charge so when anion and cation combine in fixed ration the the overall charge of the molecule is zero that is molecule is neutral. Size of cation is always smaller than anion. So, C⁴⁻ is the largest among all.

Therefore, C⁴⁻ is the largest among all.

brainly.com/question/13692734

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Solution 2

Bi3+ has 103

C4- has 170

Li+ 76

Na+102

Cl-185

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