the heat of fusion of palmitic acid (a saturated fatty acid found in meats,

the heat of fusion of palmitic acid (a saturated fatty acid found in meats, etc.) is 39.18 cal/gram at its melting point. the chemical formula for palmitic acid is c16h3202. its molecular weight is 256. how many calories of heat energy are needed to convert 0.5 mole of palmitic acid from a solid to a liquid at its melting point?

2 months ago

Solution 1

Guest Guest #2391369
2 months ago

Answer:

5015.04 cal

Explanation:

The heat of fusion is the heat needed for a molecule to change its form from solid to liquid(melting). The molecular weight for palmitic acid is 256 and you have 0.5 moles, then the number of palmitic acids you have in grams will be:

0.5 moles * (256g/mole)= 128g.

You have 128 g of palmitic acid and its heat of fusion is 39.18 cal/g. The total number of calories you need to melt it all will be: 128g  * 39.18cal/g= 5015.04 cal

📚 Related Questions

Question
Looking for the products in a single replacement formula for: MgI2 + Cl2
Solution 1

Answer: MgI2 + Cl2 ⇒ MgCl2 + I2

Explanation: The reaction produced Magnesium chloride  MgCl2 and Iodine I2. Also the chemical reaction is already balanced.

Question
What type of reaction is the equation 2NaCI 2Na+CI2 decomposition single displacement synthesis
Solution 1

Answer: Decomposition

Explanation: In a decomposition reaction it is expressed in this generic form:

AB => A + B

where A is a metal and B is a nonmetallic element.

Question
Iron + sulfur - iron(II) sulfide
Solution 1

Answer:

a

Explanation:

a

Question
Two___ of the element sodium combine with one___ of the element chlorine to form the ___ sodium chloride
Solution 1

Answer:

third, fourth

Explanation:

Question
1. Calculate the wavelength (in nm) of the red light emitted by a barcode scanner that has a frequency of 4.62 x 1014 5-1. 649.4 nm
Solution 1

Answer:

                       6.49 × 10⁻⁷ m    (or)     649 nm

Explanation:

Wavelength and Frequency are inversely proportional to each other. Greater the wavelength smaller the frequency and vice versa.

Solution:

The relation between wavelength and frequency is as follow,

                                             υ = c / λ

where

           υ = frequency = 4.62 × 10¹⁴ s⁻¹

           c = velocity of light = 3.0 × 10⁸ ms⁻¹

           λ = wavenumber = ??

Solving above equation for λ.

                                             λ  =  c / υ

Putting the given values,

           λ = 3.0 × 10⁸ ms⁻¹ / 4.62 × 10¹⁴ s⁻¹

Result:

           λ = 6.49 × 10⁻⁷ m    (or)     649 nm

Question
A crime lab received a 235-gram sample. The sample had a molecular mass of 128.1 grams and the empirical formula is CH2O. How many grams of each element are in the sample?
Solution 1

Answer: 106.9

Explanation:

Question
What are some things we breathe in
Solution 1

Answer:

The majority of the air we breathe is made up of nitrogen and oxygen, though you'll also find argon, carbon dioxide and other gases in trace amounts.

Explanation:

Question
4. A 1,750 kg weather satellite moves in a circular orbit with a gravitational potential energy of 1.69 x 100 J. At its location, free-fall acceleration is only 6.44 m/s?. How high above Earth's surface is the satellite?
Solution 1

Explanation:

It is known that the value of free fall acceleration is g = 6.44 m/s^{2}. And, the value of radius of Earth is 6.4 \times 10^{6} m.

Let us assume that height of the satellite is h.

It is known that,

             g = \frac{GM}{r^{2}}        

where,   r = (R + h)

Hence,  

              r = \sqrt{\frac{GM}{g}}

              r = \sqrt{\frac{6.67 \times 10^{-11} \times 5.98 \times 10^{24}}{6.44 m/s}}

                = 7.9 \times 10^{6} m

Now, formula for height of satellite above the Earth's surface is as follows.

            h = r - R

               = 7.9 \times 10^{6} - 6.4 \times 10^{6}

               = 1.5 \times 10^{6} m

Thus, we can conclude that the satellite is 1.5 \times 10^{6} m high above Earth's surface.

Solution 2

The height of the satellite moving in a circular orbit above the Earth's surface is the satellite is; 1.5 × 10⁶ m

What is the height of gravitational fall?

The formula to find the height of the satellite above the earth's surface is; h = [√(GM/g)] - R

where;

G is gravitational constant = 6.67 × 10⁻¹¹ N.m²/kg²

M is mass of earth = 5.98 × 10²⁴ kg

g is free fall acceleration = 6.44 m/s²

R is radius of earth  6400000 m

Thus;

h = [√(6.67 × 10⁻¹¹ × 5.98 × 10²⁴/6.44)] - 6400000

h = 1.5 × 10⁶ m

Read more about height of gravitational fall at; brainly.com/question/14460830

Question
The substances that begin a chemical reaction are called
Solution 1

Answer: Reactants

Explanation: Reactants are the initial substances that reacts to form products in a chemical reaction.

Question
A 0.15 mol sample of H2S is placed in a 10 L reaction vessel and heated to 1132◦C. At equilibrium, 0.03 mol H2is present. Calculate the value of Kc for the reaction2 H2S(g)⇀↽2 H2(g) + S2(g)at 1132◦C
Solution 1

Answer: The value of the equilibrium constant is 0.00009.

Explanation:

Initial moles of  H_2S = 0.15 mole

Volume of container = 10 L

Initial concentration of H_2S=\frac{moles}{volume}=\frac{0.15moles}{10L}=0.015M  

Moles of H_2 at equilibrium= 0.03 mole

equilibrium concentration of H_2=\frac{moles}{volume}=\frac{0.03moles}{10L}=0.003M [/tex]

The given balanced equilibrium reaction is,

                            2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

Initial conc.           0.015 M                     0     0

 At eqm. conc.    (0.015-2x) M           (2x) M   (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}

K_c=\frac{(2x)^2\times x}{(0.015-2x)^2}

we are given : 2x= 0.003 M

x= 0.0015 M

Now put all the given values in this expression, we get :

K_c=\frac{(0.003)^2\times 0.0015}{(0.015-0.003)^2}

K_c=0.00009

Thus the value of the equilibrium constant is 0.00009.