The length of a rectangle is 5 yd longer than its width. If the perimeter of the rectangle is 38 yd , find its area.
2 months ago
Solution 1
2 months ago
L=5+W
P=2(L+W)
38=2(L+W)
divide by 2
19=L+W
sub 5+W for L
19=5+W+W
19=5+2W
minus 5 both sides
14=2W
divid both sides by 2
7=W
L=5+W
L=5+7
L=12
area=LW
are=12 times 7
area=84 yd²
P=2(L+W)
38=2(L+W)
divide by 2
19=L+W
sub 5+W for L
19=5+W+W
19=5+2W
minus 5 both sides
14=2W
divid both sides by 2
7=W
L=5+W
L=5+7
L=12
area=LW
are=12 times 7
area=84 yd²
📚 Related Questions
Question
Which expression is equivalent to the given expression? 8(3/4a)−8
1. 3/4a
2. 6a
3. 8(3/4a - 1)
4. 3/4a -1
Solution 1
Answer:
The correct option is 3.
Step-by-step explanation:
The given expression is
The factors of each term are
The common factor is 8.
Take out the common factor from the given expression.
Therefore option 3 is correct.
Solution 2
8(3/4a)−8 = 8(3/4a - 1)
answer 3. 8(3/4a - 1)
answer 3. 8(3/4a - 1)
Question
PLZ HLP ASAP!!! A park is 2000 hectares in area. If the park is square, what would be the length of each side in kilometers, to the nearest tenth of a kilometer? (1 square kilometer = 100 hectares)
Solution 1
(1 square kilometer = 100 hectares). hope this helps you out but idk the answers so only thing i can do is give u help but hope it helps you :)
Question
Find all the zeros. SHOW ALL WORK!
5x^3 – 5x = 0
Thank you for your help :)
Solution 1
Factor
remember
if xy=0, assume that x and y=0
also
difference of 2 perfect squares
a²-b²=(a-b)(a+b)
so
5x³-5x=0
factor out 5x
5x(x²-1)=0
5x(x²-1²)=0
factor perefect square
5x(x-1)(x+1)=0
set each to zero
5x=0
x=0
x-1=0
x=1
x+1=0
x=-1
x=-1 or 0 or 1
remember
if xy=0, assume that x and y=0
also
difference of 2 perfect squares
a²-b²=(a-b)(a+b)
so
5x³-5x=0
factor out 5x
5x(x²-1)=0
5x(x²-1²)=0
factor perefect square
5x(x-1)(x+1)=0
set each to zero
5x=0
x=0
x-1=0
x=1
x+1=0
x=-1
x=-1 or 0 or 1
Question
Sn: 1 ∙ 2 + 2 ∙ 3 + 3 ∙ 4 + . . . + n(n + 1) = [n(n + 1)(n + 2)]/3
Solution 1
Steps to inductive
1. show it's true for n=1
2. replace n with k
3. replace k with k+1 and show it is true statement
4. state that it's true
1. show it's true for n=1
1(1+1)=[1(1+1)(1+2)]/3
1(2)=[(2)(3)]/3
2=6/3
2=2
true
2. assume it's true for n=k
1*2+2*3+3*4+...+k(k+1)=[k(k+1)(k+2)]/3
3. show it's true for replaceing k with k+1
1*2+2*3+3*4+...+k(k+1)+(k+1)((k+1)+1)=[(k+1)((k+1)+1)((k+1)+2)]/3
remember from before that 1*2+2*3+3*4+...+k(k+1)=[k(k+1)(k+2)]/3
[k(k+1)(k+2)]/3+(k+1)(k+2)=[(k+1)(k+2)(k+3)]/3
use algebra to show this is true (get it to k=k or something like that)
here's the fun part
deal with left side to get to like right side
[k(k+1)(k+2)]/3+(k+1)(k+2)
make over 3, so muliptlu 2nd thing by 3/3
[k(k+1)(k+2)]/3+((k+1)(k+2)3)/3
[k(k+1)(k+2)+3(k+1)(k+3)]/3
we can undistribute the (k+1)(k+2) part
[(k+1)(k+2)(k+3)]/3
now remember the right side?
[(k+1)(k+2)(k+3)]/3=[(k+1)(k+2)(k+3)]/3
tada
true
4. state it
therefor 1 ∙ 2 + 2 ∙ 3 + 3 ∙ 4 + . . . + n(n + 1) = [n(n + 1)(n + 2)]/3 is true for all real numbers
1. show it's true for n=1
2. replace n with k
3. replace k with k+1 and show it is true statement
4. state that it's true
1. show it's true for n=1
1(1+1)=[1(1+1)(1+2)]/3
1(2)=[(2)(3)]/3
2=6/3
2=2
true
2. assume it's true for n=k
1*2+2*3+3*4+...+k(k+1)=[k(k+1)(k+2)]/3
3. show it's true for replaceing k with k+1
1*2+2*3+3*4+...+k(k+1)+(k+1)((k+1)+1)=[(k+1)((k+1)+1)((k+1)+2)]/3
remember from before that 1*2+2*3+3*4+...+k(k+1)=[k(k+1)(k+2)]/3
[k(k+1)(k+2)]/3+(k+1)(k+2)=[(k+1)(k+2)(k+3)]/3
use algebra to show this is true (get it to k=k or something like that)
here's the fun part
deal with left side to get to like right side
[k(k+1)(k+2)]/3+(k+1)(k+2)
make over 3, so muliptlu 2nd thing by 3/3
[k(k+1)(k+2)]/3+((k+1)(k+2)3)/3
[k(k+1)(k+2)+3(k+1)(k+3)]/3
we can undistribute the (k+1)(k+2) part
[(k+1)(k+2)(k+3)]/3
now remember the right side?
[(k+1)(k+2)(k+3)]/3=[(k+1)(k+2)(k+3)]/3
tada
true
4. state it
therefor 1 ∙ 2 + 2 ∙ 3 + 3 ∙ 4 + . . . + n(n + 1) = [n(n + 1)(n + 2)]/3 is true for all real numbers
Question
Which expression is equivalent to the given expression? 8(3/4a)−8
1. 3/4a
2. 6a
3. 8(3/4a - 1)
4. 3/4a -1
Solution 1
Answer:
Step-by-step explanation:
8 (3/4a) - 8
The above expression can be written as:
Since 8 is a common factor here which is multiple of 3/4a as well as 1 therefore taking 8 as a common factor from whole equation,
Therefore option (3) is the correct answer.
Solution 2
The answer is 3 cause we can factor 8 from the whole equasion .
that means to take 8 out of every given data so
since we have 8 multiple 3/4a we can have an 8 and we also have -8 so we can divide it to 8 and take 8 out of it which leads us to 8(3/4a-1)
that means to take 8 out of every given data so
since we have 8 multiple 3/4a we can have an 8 and we also have -8 so we can divide it to 8 and take 8 out of it which leads us to 8(3/4a-1)
Question
When a nonzero rational and an irrational number are multiplied, is the product rational or irrational?
Solution 1
The sum of a rational number and an irrational number is irrational.
Question
Harvey is 3 times as old as Jane. The sum of their ages is 48 years. Find the age of each. Jane is a0 years old. Harvey is a1 years old.
Solution 1
Let jane = j
Harvey = 3*j = 3j
Sum = 48 years
j + 3j = 48
4j = 48
j = 48/4
j = 12
Jane, j = 12 years old
Harvey, 3j = 3*12 = 36 years old
Hope this helped.
Harvey = 3*j = 3j
Sum = 48 years
j + 3j = 48
4j = 48
j = 48/4
j = 12
Jane, j = 12 years old
Harvey, 3j = 3*12 = 36 years old
Hope this helped.
Solution 2
Harvey is 36, jane is 12
Question
When calculating the effective rate of a loan, which statement or statements must be true if n is greater than 1? I. The length of the loan is greater than a single year.
II. The effective rate will exceed the nominal rate.
III. The interest will be compounded monthly.
Solution 1
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
When calculating the effective rate of a loan, the statement or statements must be true if n is greater than 1 is The length of the loan is greater than a single year.
When calculating the effective rate of a loan, the statement or statements must be true if n is greater than 1 is The length of the loan is greater than a single year.
Solution 2
Answer: A
Step-by-step explanation:
its a
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All equilateral triangles are also isosceles triangles.
TRUE OR FALSE?
Solution 1
false kljfoidjfdiojfoidjfoijfoidjfodijfoidjf
Solution 2
Answer:
I think it's true but not 100% sure :)
Step-by-step explanation:
Question
Which expression is equivalent to the given expression? −(2n−6)
1. −2(n−3)
2. −2(n−6)
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4. 2n + 6
Solution 1
−(2n−6)
= -2n + 6
= -2(n - 3)
answer is 1. −2(n−3)
= -2n + 6
= -2(n - 3)
answer is 1. −2(n−3)
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