The perimeter of a triangle is 140 inches. If one side of the triangle is 13 more than the shortest side, and the longest side is 31 more than the shortest side, find the lengths of the three sides? side 1 = side 2= side 3=
2 months ago
Solution 1
2 months ago
You Have to add 13 EverySide
Solution 2
2 months ago
Let the shortest side be x.
one side is 13 more than the shortest = x + 13
Longest is 31 more than the shortest = x + 31
Perimeter of triangle = 140
x + x + 13 + x + 31 = 140
3x + 44 = 140
3x = 140 - 44
3x = 96
x = 96/3
x = 32
Shortest side, x = 32
Other side = x + 13 = 32 + 13 = 45
Longest side = x + 31 = 63
Side 1 = 32 inches
Side 2 = 45 inches
Side 3 = 63 inches
I hope this helped.
one side is 13 more than the shortest = x + 13
Longest is 31 more than the shortest = x + 31
Perimeter of triangle = 140
x + x + 13 + x + 31 = 140
3x + 44 = 140
3x = 140 - 44
3x = 96
x = 96/3
x = 32
Shortest side, x = 32
Other side = x + 13 = 32 + 13 = 45
Longest side = x + 31 = 63
Side 1 = 32 inches
Side 2 = 45 inches
Side 3 = 63 inches
I hope this helped.
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hope this helps :)
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