The vapor pressure of ethanol at 25°C is 7.828 kPa . Calculate the vapor pressure in atm .

2 months ago

Solution 1

Guest #6877037
2 months ago
First you get 7.83 kPa = 7.83 * 10^4 Pa Then convert it to atm by using the relation 1 Pa = 9.8692 * 10^-6 atm, this gives you 7.83 kPa = 7.83 * 10^4 * 9.8692 * 10^-6 atm = 77.275836 * 10^-2 atm = 0.77275836 atm Now round to three significant digits, = 0.773 atm

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[H+] = 10^-2.68 = 0.00209M = [PAc-]
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Ka = (.00209)(.00209) / (0.083) = Answer Here.

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